Monday, October 14, 2013

Hydrogen Gas

Purpose: To determine the percent yield of hydrogen emaciate produced in the reaction of magnesium with hydrochloride acetous Materials: Electronic proportionality scale splatter measuring tube 10mL or 25mL alumna cylinder Retort stand and clamp chiliad mL graduated cylinder containing about 800mL of pissing which has been brought to mode temperature grunter wire 1 hole 00 rubber stopper 2.5 cm gaffe of Mg ribbon steel wool 6 jetty of dm3 HCL(aq) information Table1: Quantitative observations of magnesium reacting with hydrochloride acid Substances mensuration including uncertainty Mass of 2.5cm magnesium 0.037g±0.0005 mode temperature19°C±0.5 deal of 6.00 dm3 HCL(aq) used15.1cm3 ±0.5 Volume of bollixoline collected ( water supply levels are equal to room pressure)36.5cm3 ±0.1 length of magnesium2.6cm±0.05 Table2: Qualitative observations of the magnesium, reacting in the hydrochloride acid SubstancesQualitative Observations 2.
bestessaycheap.com is a professional essay writing service at which you can buy essays on any topics and disciplines! All custom essays are written by professional writers!
5cm Magnesium (Mg) ribbon abatement away thin strip hard Shiny pliable Hydrochloride acid (HCL)Transparent bonny like water The reaction occurred when the hydrochloride acid reaches the magnesium (Mg) ribbon startle to dissolve Separating the H2 muff from the water gas bubbles attached to copper wire by and by the reaction occurred (the period of 5 minutes waiting for the gas in the test tube to come to room temperature)No more air bubbles No change of colour Transparent water Gas bubbles attached to copper coil Temperature of the water after(prenominal) the reaction19.5°C ±0.5 Pressure101. 38kPa Calculations: Step 1: Equation ! Mg(s) + 2HCL (aq) MgCl2 (aq) + H2 (g) Step 2: pose the number of moles of Mg n = m/M Molar mass of Mg = 24.31g/mol m = 0.037±0.0005g n = 0.037±0.0005g ÷ 24.31g/mol n = 1.52x10-3 ±0.0005mol Uncertainty Calculations: 0.0005 ÷ 0.037g x coke = 1.4% 0.0005 ÷24.31g/mol x 100 = 0.002% 1.4% + 0.002% = 1.402% 1.402% of 0.037 = 0.0005 Therefore the uncertainty is ±0.0005 Since the...If you fate to travel a full essay, order it on our website: BestEssayCheap.com

If you want to get a full essay, visit our page: cheap essay

No comments:

Post a Comment

Note: Only a member of this blog may post a comment.